What do I NEED to create a txt file which lists and counts files in folders. Directory and sub directory

For Example:

c:Test\List of Folders

Folder Name: Number of Files

Folder 1: 32 (files/docs)

Folder 2: 28 (files/docs)

Folder 3: 23 (files/docs)

And a more tricky QUESTION, if the folder contains .docs created by a mailmerge, is it possible to return the number of letters contained within the mailmerge?

I mailmerge would contain multiple individual letters
ECHO OFF
set c=0
:TOP
for /f "tokens=1*" %%a in ('dir /a * /b /s') do (
       call set /a c=%%c%%+1
)
CLS&ECHO %c% Files.





place it in the folder you want a file count in, or place it in your root folder to count all files on your system,  the /a switch includes hidden files and the /s switch includes all sub directorysThanks Diablo

But it doesn't work, the command just sits

would like it to be placed in a txt file tosorry it does work

added pause so i could see

how do i add it to a txt file.

and break it down so it lists the sub-directories with each amountI'm really trying

cmd /c "dir C:\Users\Jbloggs\Desktop\bbs > c:\temp\output.txt"

it returns:

 Volume in drive C is OS
 Volume Serial Number is xxxxxxxx

 Directory of C:\Users\JbloggsDesktop\bbs

08/12/2008  20:01              .
08/12/2008  20:01              ..
08/12/2008  20:26                63 co1.bat
03/12/2008  15:41              test1
03/12/2008  16:48              test2
               1 File(s)             63 bytes
               4 Dir(s)  395,136,864,256 bytes free

How do I tweak it, to read in a more plain english


This may help:

Code: [Select]echo off
setlocal enabledelayedexpansion
set folder=C:\Users\Jbloggs\Desktop\bbs
for /f "tokens=* delims=" %%v in ('dir /a:d /s /b "%folder%"') do (
for /f "tokens=* delims=" %%i in ('dir /a:-d /b "%%v" 2^>^&1') do (
if /i %%i NEQ "File Not Found" call set /a count=%%count%%+1
)
echo %%v: !count! (files/docs^)
set count=0
)

Be sure to set the folder variable correctly.

Good luck.

EDIT: In the interest of accuracy and future readers, the code was modified to correct a syntax error.i think may a bit more difficult than expected

appreciate the help, sidewider. your code works, but i don't need to see the file path and want it to display in txt file

but what i'm after is

a simple display to a txt file

List the directory of folders and sub folders with how much files each contains

ie

Folder 1 = 34
Folder 2 = 23
etc

i'm learning alot for you guys.. thanksA tweak here, a tweak there, soon you have a new variation of the same old song:

Code: [Select]echo off
setlocal enabledelayedexpansion
set folder=C:\Users\Jbloggs\Desktop\bbs
for /f "tokens=* delims=" %%v in ('dir /a:d /s /b "%folder%"') do (
for /f "tokens=* delims=" %%i in ('dir /a:-d /b "%%v" 2^>^&1') do (
if /i %%i NEQ "File Not Found" call set /a count=%%count+1
)
echo %%~nv: !count! >> textfile.txt
set count=0
)

As before, make sure the folder variable is set correctly. For a lack of imagination, the output file is labeled textfile.txt

Quote

And a more tricky question, if the folder contains .docs created by a mailmerge, is it possible to return the number of letters contained within the mailmerge?

With regards to the mailmerge. These are number of letters (.doc) contained within word.

To split I have the start and end of each letter identified with a flag

<begin> and <end>