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Solve (D2 + 2D + 3) y = 0 differential equations. |
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Answer» The auxiliary equations A.E is m2 + 2m + 3 = 0 ⇒ m2 + 2m + 1 + 2 = 0 ⇒ (m + 1)2 = -2 ⇒ m + 1 = ± √2i ⇒ m = – 1 ± √2i It is of the form α ± iβ The complementary function (C.F) = e-x [A cos √2 x + B sin √2 x] The general solution is y = e-x [A cos √2 x + B sin √2 x] |
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