|
Answer» Here is a sample of the text file:
~ === SALES Order Confirmation Message === ~ Customer: 0023410 ~ **** Delivery Date Exception. Promised Date greater than Required Date. **** ~ Required Date: Thu 10-Nov-11 Promised Date: Fri 11-Nov-11 ~ NEW Sales Order: 1343943 | OW Order: 1436
I would like to delete the first character of every line. I've tried doing find and replace, but can't seem to get it to work. Any help would be appreciated.
Code: [SELECT]echo off
setlocal enabledelayedexpansion
for /F "tokens=*" %%A in (myfile.txt) do ( set line=%%A echo !line:~1! >> newfile.txt )
Replace myfile.txt and newfile.txt with your own.Add in this at the end (outside the parenthesis) to make it transparent:
Code: [Select]del myfile.txt ren newfile.txt myfile.txt
|