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Solve : Determining what is in a text file via batch?

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Hi all, how would i go about making a batch file that reads a text file, and if the text file contains a certain word, execute a certain action?

Eg. i want my batch file to check if text file EXAMPLE.txt has EXAMPLEWORD in it, and if it does i want the batch file to continue with the code, or not do ANYTHING if EXAMPLEWORD is not found.

Thanks in advance,

KamakCode: [Select]for /f "tokens=* delims=" %%v in ('type example.txt ^| find "EXAMPLEWORD"') do echo %%v

This example executes the echo instruction if the argument is found. You can change this to whatever instruction you want executed. The search for EXAMPLEWORD is case sensitive. Add the /i SWITCH to the find command to make it case insensitive.

Happy coding, I am sure findstr takes in a file as input
Code: [Select]findstr /I /G:file "STRING to SEARCH" && execute_command
Findstr takes a file or receives an input via a pipe as Sidewinder's example shows.
Quote from: Dias de VERANO on May 16, 2008, 09:35:26 AM

Findstr takes a file or receives an input via a pipe as Sidewinder's example shows.

yup, so using type would be unnecessary , not that its a big deal anyway Quote from: ghostdog74 on May 16, 2008, 09:14:21 AM
I am sure findstr takes in a file as input
Code: [Select]findstr /I /G:file "STRING to SEARCH" && execute_command

findstr /I "String to search" filename.txt>nul && execute_commandThanks all, you've been really helpful


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