Solve : display content of a list within a variable?

1.	Solve : display content of a list within a variable?
Answer» Hi, I have a variable LIST=ELEM1;ELEM2;ELEM3 which command should I call to have for results ELEM1 ELEM2 ELEM3 if I do the following command line; I do have only the first element of the list (while the other are probably in %J and so on) > for /F "delims=;" %i in ("%LIST%") do echo %i ELEM1 note that I do construct the LIST, so I can CHANGE the delimiters or the FORMAT if required. thanks found by myself I change my list format to have space as delimiters LIST=ELEM1 ELEM2 ELEM3 SET AUTO_VARIABLE_LIST=%LIST% :FOR_LOOP for /f "tokens=1* " %%i in ("%AUTO_VARIABLE_LIST%") do ( call echo %%i set AUTO_VARIABLE_LIST=%%j ) if "%AUTO_VARIABLE_LIST%"=="" GOTO :END_LOOP else ( GOTO :FOR_LOOP ) :END_LOOP

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