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Solve : Dos Batch Variables?

Answer»

Looking for a was to restate  if "!LINE!"=="19"  in the following example to accept a variable Example: if "!LINE!"==%value% 


SET S=%%i
SET LINE=0
for /F "delims=" %%L in (%FILE%) do (
        set /A LINE += 1
        if "!LINE!"=="19" (
                set STR=%%L
                echo. !STR:~8!> %TEMP%.\T1.DAT
                FINDSTR /B /C:"TLAXIS" %TEMP%.\T1.DAT > nul
                del %TEMP%.\T1.DAT
                                if not errorlevel=1 (
                            set NAME=%FILE%.vec
                        copy %FILE% %LOC%\%FILE%.vec
      cls
         echo.Looking for a way to restate   if "!LINE!"=="19"  in the following example to accept a variable!    Example: if "!LINE!"==%value% 
(before the FOR statement)
set value=19

(in the loop)
if "!LINE!"=="%value%" (

or

if !LINE! equ %value% (THANK YOU AGAIN!  Works PERFECT!



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