DOS supports the use of wildcards using a ? [question mark].  I have files of all different names, but I am looking for files that meet a specific criteria:

I have files of the names:
 
somename.csv
abc2ee.csv
file344.csv
debt32.csv
....
somename1108112.csv   &LT;< i want this >>
abc2ee1108112.csv         << i want this >>
file3440822451.csv        << i want this >>
debt321008213.csv        << i want this >>
....

The number PART of the above files can be any number, is there a way to replace something like Code: [Select]somename???????.csv, that is, insteading of typing so many question marks like use some multiplier?

While I am on the subject, how can I say give me EVERY file which is preceeded only by7 digits before the ".csv"?


THANKS....dir somename*.csv      --> lists any file starting with somename and with csv extension

Regarding last question, i don't remember well, but i think you cannot combine both wildcards ("?" and "*") in the same expression. So [i think] you can search for a file with exactly n digits, but not at least n digits. I mean, you can do

dir .csv   --> will list any 3-digit filename with csv extension

but you can't do

dir *.csv   --> Error. Cannot combine both wildcards.


In case anyone is interested, here is what I have DONE to resolve my issue:

REM  Perform a "dir" on the SOURCE_PATH, and then save a list of all files which
REM  have the extension ".csv" preceeded by 6 digits.
REM
dir /B %%SOURCE_PATH%% | findstr ".*[0-9][0-9][0-9][0-9][0-9][0-9]\.csv" > tmp.txt
........