Solve fastt.. plz zzz

1.	Solve fastt.. plz zzz
Answer» <P> $\Large{\underline{\underline{\tt{\purple{Given}}}}}$ FORCE (F) = 48000N Pressure (P) = 120 P $\Large{\underline{\underline{\tt{\purple{Find\:out}}}}}$ Find the area of base ? $\Large{\underline{\underline{\tt{\purple{Solution}}}}}$ As we know that $\begin{gathered}\implies\sf P=\dfrac{F}{A} \\ \\ \\ \implies\sf 120=\dfrac{48000}{A} \\ \\ \\ \implies\sf 120A=48000 \\ \\ \\ \implies\sf A=\cancel\dfrac{48000}{120}=400m^2\end{gathered}$ $\large{\underline{\boxed{\bf{\red{Area\:of\:statue=400m^2}}}}}$ $\Large{\underline{\underline{\tt{\purple{Extra\: Information}}}}}$ —: Acceleration = v - u/t —: Force = mass × acceleration —: SPEED = distance/time

Answer»

<P> $\Large{\underline{\underline{\tt{\purple{Given}}}}}$

FORCE (F) = 48000N

Pressure (P) = 120 P

$\Large{\underline{\underline{\tt{\purple{Find\:out}}}}}$

Find the area of base ?

$\Large{\underline{\underline{\tt{\purple{Solution}}}}}$

As we know that

$\begin{gathered}\implies\sf P=\dfrac{F}{A} \\ \\ \\ \implies\sf 120=\dfrac{48000}{A} \\ \\ \\ \implies\sf 120A=48000 \\ \\ \\ \implies\sf A=\cancel\dfrac{48000}{120}=400m^2\end{gathered}$