solve for x: `9x^2-6b^2x-(a^4-b^4)=0` – InterviewSolution

InterviewSolution

1.	solve for x: `9x^2-6b^2x-(a^4-b^4)=0`
Answer» `x=(6b^2pmsqrt(6b^2)^2-49(-a^4-b^4))/(29)` `x=(6b^2pm6a^2)/18` `x=(b^2pma^2)/3` `x=(b^2+a^2)/3,(b^2-a^2)/3`.

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