Solve for x and y

1.	Solve for x and y
Answer» ANSWER: $<klux>X</klux> = \frac{2}{3}$ $y = \frac{1}{3}$ Step-by-step EXPLANATION: $= > \frac{x + y}{xy} = \frac{9}{2} \\ = > 2x + 2y = 9xy - - - (i)$ And ALSO, $= > \frac{x - y}{xy} = \frac{3}{2} \\ = > 2x - 2y = 3xy - - - - (ii)$ Solving (i) and (ii) ${ = > (2x + 2y) - (2x - 2y) = 9xy - 3xy}$ $= > 2x + 2y - 2x + 2y = 6xy$ $= > 4y = 6xy$ $= > \frac{4y}{6y} = x$ $= > x = \frac{2}{3}$ Substituting x in (i) :- $= > 2x + 2y = 9xy$ $= > 2(x + y) = 9xy$ $= > 2( \frac{2}{3} + y) = 9( \frac{2}{3} )y$ $= > 2( \frac{2 + 3y}{3} ) = \frac{18y}{3}$ $= > \frac{4 + 6y}{3} = \frac{18y}{3}$ $= > 4 + 6y = 18y$ $= > 4 = 18y - 6y$ $= > 4 = 12y$ $= > y = \frac{1}{3}$

Answer»

$<klux>X</klux> = \frac{2}{3}$