Solve for x and y, given that `[{:(x,y),(3y,x):}][{:(1),(2):}]=[{:(3),(5):}].`

Solve for x and y, given that `[{:(x,y),(3y,x):}][{:(1),(2):}]=[{:(3),

1.	Solve for x and y, given that `[{:(x,y),(3y,x):}][{:(1),(2):}]=[{:(3),(5):}].`
Answer» We have `[{:(x,y),(3y,x):}][{:(1),(2):}]=[{:(3),(5):}]` `implies" "[{:(x+2y),(3y+2x):}]=[{:(3),(5):}]` `implies" "{{:(x+2y=3" "...(i)),(2x+3y=5" "...(ii)):}` Multiplying (i) by 2 and subtracting (ii)from it, we get y=1. Putting y=1 in (i), we get x=1. Hence, x=1 and y=1.

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Solve for x and y, given that `[{:(x,y),(3y,x):}][{:(1),(2):}]=[{:(3),(5):}].`

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