Solve for x and y of the following eq. ax+by=b=13 bx-ay=-a-b

1.	Solve for x and y of the following eq. ax+by=b=13 bx-ay=-a-b
Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><p>The <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> <a href="https://interviewquestions.tuteehub.com/tag/system-1237255" style="font-weight:bold;" target="_blank" title="Click to know more about SYSTEM">SYSTEM</a> of equations <a href="https://interviewquestions.tuteehub.com/tag/may-557248" style="font-weight:bold;" target="_blank" title="Click to know more about MAY">MAY</a> be written as</p><p>ax+by−(a−b)=0</p><p>bx−ay−(a+b)=0</p><p></p><p></p><p>By cross-multiplication, we get</p><p></p><p></p><p>⇒b×−(a+b)−(−a)×−(a−b)<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>=a×−(a+b)−b×−(a−b)−y=−a2−b21</p><p></p><p>⇒−b(a+b−a(a−b)x=−a(a+b)+b(a−b)−y=−(a2+b2)1</p><p></p><p>⇒b2−a2x=−a2−b2−y=−(a2+b2)1</p><p></p><p>⇒−(a2+b2)x=</p><p></p><p></p></body></html>

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