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Solve for x :- x² + ( 4 - 3y ) x - 12y = 0​

Answer»

QUESTION:

Solve for x:

x2 + (4 – 3Y)x – 12Y = 0

Solution:

Here, x2 + 4x – 3XY – 12y = 0

⟹ x(x + 4) - 3y(x + 4) = 0

or, (x + 4) (x – 3y) = 0

⟹ x + 4 = 0 or x – 3y = 0

⟹ x = -4 or x = 3y

Therefore, x = -4 or x = 3y



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