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Answer» hi? how are you?
I want to get file NAME in ms-dos batch program
but I want to apart of file name.
for example,
c:\kk\20041220\CGAA0_ROLE_20041220.txt
---> I want to get " CGAA0 " then
INSERT below variable XXX
ECHO open 111.111.44.78 > FTPHEAD.SCR
ECHO lsy>> FTPHEAD.SCR
ECHO lsy01>> FTPHEAD.SCR
ECHO bi >> FTPHEAD.SCR
ECHO hash >> FTPHEAD.SCR
ECHO prompt >> FTPHEAD.SCR
ECHO put XXX_ROLE_20041220.txt >> FTPHEAD.SCR
ECHO bye >> FTPHEAD.SCR
ftp -s:FTPHEAD.SCR > Dashboard_Log_quit_20041220.logTry something like this:
CODE: [Select]set v=c:\kk\20041220\CGAA0_ROLE_20041220.txt
for /f "tokens=4 delims=_\" %i in ("%v%") do echo %i
The for loop breaks the variable v into several pieces, separated by either _ or \. It then assigns the 4th piece to the variable i.
Good luck,
[GLB]cs[/glb]Remember in DOS, filenames are limited to 8 charectors in length, plus 3 for an extention.
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