Hey all

I'm trying to test a variable and if its correct open up another batch file, if its false go to another part of the original .bat file. Below is how Ive got my commands :

IF %VARIABLE% == 1 (
CALL TEST.BAT
)ELSE(
GOTO TEST2
)

But it generates this output without running the 2nd .bat file. PROMPT outputs "ELSE( was UNEXPECTED at this time". Ive tried changing the format but I cant get it to work.

Would this be the right way of doing it, or is there a better way.

Thanks, Alextry;

if /i "%variable%" EQU "1" (start test.bat) else goto test2


notice I added "/i" this will MAKE the if statement compare them as integers. I've also added the " " around the values we're comparing and I stuck it on one line cos I reakon it's easier to read.

I haven't tested it, but I hope it helps. Quote from: blastman on May 09, 2008, 08:30:06 AM

notice I added "/i" this will make the if statement compare them as integers.

I've also added the " " around the values we're comparing

and I stuck it on one line cos I reakon it's easier to read.

Quote from: blastman on May 09, 2008, 08:30:06 AM

notice I added "/i" this will make the if statement compare them as integers.

No it won't; using if with the /i switch makes the comparison case-insensitive, or makes it ignore case if you prefer. Since numerical digits don't have "upper" or "lower" case, it will have no effect whatsoever.

the bit that confused me...

"These comparisons are generic, in that if both string1 and string2 are both comprised of all numeric digits, then the stings are converted to numbers and a numeric comparison is performed"