How do i code a batch script to GET the most recent file from a folder. Also, I want to move this file to another location?

THANKS for the help.If you do a dir list, you can order it in reverse date order (newest at the top) - thus
DIR /O-D > filelist.txt

This command puts the first line of a file (the newest filename) into the environment variable

SET /P NewestFile=
Now you can do whatever you need with the filename

GrahamThanks for the reply.

didn't seem to work for me...


The contents in the filelist.txt are


Volume in drive C has no label.
Volume Serial Number is 18C1-0B4A

Directory of c:\Copy1

03/25/2008 01:00 PM 0 3.dat
03/25/2008 10:08 AM 4 2.dat
2 File(s) 4 bytes
0 Dir(s) 52,907,216,896 bytes free


It is sorted by the date, but when I try to get the first file using "SET /P RecentFile=I fixed it..

I added the dir search with /b /s (dir /b /s /O-D *.dat >filelist.txt).

Thanks for the help again..Sorry, forgot the /B

well spotted !!
GrahamCan you give the detailed code.Here is the tweaked version that ignores directory entries (and puts the temporary file in the TEMP directory)

Code: [Select]DIR /B /O-D /A-D>%TEMP%\filelist.txt
SET /P NewestFile=<%TEMP%\filelist.txt
ECHO %NewestFile%
DEL %TEMP%\filelist.txt
GrahamQuote from: cbvidya on March 25, 2008, 10:31:52 AM

How do i code a batch script to get the most recent file from a folder. Also, I want to move this file to another location?

Thanks for the help.