Hi There,

I am unable to find a solution to get the free space available on the disk drives and mount volumes (in windows server). i am looking for a command or batch file where i can get output like this. Drive F: has several mount points. How do i get an output like this in MB. This a sample in KB

Name Capacity Free space PercentFree
---- -------- --------- -----------
C:\ 146777567232 101463191552 69.13 %
E:\ 68713955328 67994939392 98.95 %
Q:\ 1069253632 1061010432 99.23 %
O:\ 68713955328 21001535488 30.56 %
P:\ 68713955328 68644261888 99.90 %
F:\ 68713955328 68644233216 99.90 %
F:\D01\ 1642818691072 19775197184 1.20 %
F:\RRep\ 68713955328 68644286464 99.90 %
F:\D033\ 549761228800 21194547200 3.86 %
F:\D02\ 1642818691072 36596097024 2.23 %
F:\Bkup\ 1642818691072 1419910320128 86.43 %
F:\D04\ 1095212449792 4592365568 0.42 %
F:\T01\ 1095212449792 815251521536 74.44 %
F:\TDB\ 1095212449792 56733552640 96.49 %

regards
HelenThis should help you: http://stackoverflow.com/questions/2539262/how-to-find-the-percentage-of-free-space-for-mapped-drivesthanks very much Linux711Hi Linux711,

the solution found in the link does not solve the problem.

for /f "usebackq delims== tokens=2" %%X in (`wmic logicaldisk where "DeviceID='C:'" get FreeSpace /format:value`) do set FreeSpace=%%x
for /f "usebackq delims== tokens=2" %%x in (`wmic logicaldisk where "DeviceID='C:'" get Size /format:value`) do set Size=%%x
set FreeMB=%FreeSpace:~0,-6%
set SizeMB=%Size:~0,-6%
set /a Percentage=100 * FreeMB / SizeMB
echo C: is %Percentage% % free

it only gives me the space avaible on a disk and not on mounted volume. Also you got to pass each drive letter as an argument to the file

Any other help please?


thanks

HelenHey All,

I found out the command that helps me to get volume information

wmic Volume get Name, Capacity, FreeSpace

Can someone help me to format it neatly and get the size in GB and get the % free

thanks
HelenDoes WMIC in that command report your mount points too? Is that an issue?

Batch math can only natively handle 2^31 - 1 so you will have to resort to WSH or Powershell for the math.
Batch code does not support floating point arithmetic and numbers are limited to 32 bit PRECISION. An alternate solution would be VBScript.

Code: [Select]strComputer = "."
Set objWMIService = GetObject("winmgmts:" _
& "{impersonationLevel=impersonate}!\\" & strComputer & "\root\cimv2")

Set colDisks = objWMIService.ExecQuery _
("Select * from Win32_LogicalDisk where drivetype <> 5")

WScript.Echo "Name Capacity Free Free %"
For each objDisk in colDisks
percentfree = (objdisk.Freespace / objdisk.Size) * 100
With objDisk
WScript.Echo .DeviceId & " " & pad(FormatNumber(.Size/1073741824, 2)) & " " & pad(FormatNumber(.Freespace/1073741824, 2)) & " " & FormatNumber(percentfree, 2)
End With

Next

function pad(strText)
strText = Space(10) + strText
strText = Right(strText, 8)
pad = strText
end function

Save script with a VBS extension and run from the command line as: cscript //nologo scriptname.vbs

If you have access to Powershell, that would also be a good alternate solution.
Hey foxidrive & sidewinder,
Check out Judago's website for a work around on the batch math limitations.
Judago.webs.comThanks Squashman. What a monster that batch file is! Quote from: Squashman on August 30, 2012, 07:56:21 PM

Hey foxidrive & sidewinder,
Check out Judago's website for a work around on the batch math limitations.
Judago.webs.com