I found a batch file that was supposed to keep any process open while the batch is running, but it doesn't work.
No MATTER what I do, it always says that the process is not open.

Here is the batch (Credits to Foxhound)

Code: [Select]@echo off
mode con cols=35 lines=10
title Keep a process open.
set /p ppath=Enter the folder where the process is located in:
cls
set /p pname=Enter the exact name of the process you wish to keep open:
cd %ppath%
:LOOP
cls
tasklist | find "%pname%" >nul
if %errorlevel%==1 (
color 0c
echo Program not found. Starting %pname%
start %pname%
goto WAIT
)
if %errorlevel%==0 (
color 0a
echo Program found. Skipping start.
goto wait
)
:wait
timeout /t 5 /NOBREAK >nul
goto loop

Could someone PLEASE tell me how to fix it, or have any other batch files like this that work?

Thanks

I cleaned up your code and added a TRAP to to prevent a code malfunction that would send the batch file into a loop of opening endless cmd windows.

I suspect this file does not do what you think it does. When a process in no longer on the tasklist, it will start a new instance of the program, however the previous instance will be long terminated. It will not keep a process open, just create a new one.

If there are multiple copies of a process, how do you distinguish between them?

Code: [Select]@echo off

title Keep a process open.
set /p ppath=Enter the folder where the process is located in:

set /p pname=Enter the exact name of the process you wish to keep open:
if not exist %ppath%\%pname% (
echo %ppath%\%pname NOT found
goto :eof
)
cd %ppath%

:loop
tasklist | find "%pname%" >nul
if errorlevel 1 (
color 0c
echo Program not found. Starting %pname%
start %pname%
goto wait
)

if not errorlevel 1 (
color 0a
echo Program found. Skipping start.
goto wait
)

:wait
timeout 5 >nul
goto loop