Solve : (i) 13x−6=52(ii) 2x3−3x8=712(iii) (x+2)(x+3)+(x−3)(x−2

1.	Solve : (i) 13x−6=52(ii) 2x3−3x8=712(iii) (x+2)(x+3)+(x−3)(x−2)−2x(x+1)=0(iv) 110−7x=35(v) 13(x−4)−3(x−9)−4(x+4)=0(vi) x+7−8x3=17x6−5x8(vii) 3x−24−2x+33=23−x(viii) x+26−(11−x3−14)=3x−412(ix) 25x−53x=115(x) x+23−x+15=x−34−1(xi) 3x−23+2x+32=x+76(xii) x−x−12=1−x−23(xiii) 9x+72−(x−x−27)=36(xiv) 6x+12+1=7x−33
Answer» Solve : $(i) \frac{1}{3} x - 6 = \frac{5}{2} (i i) \frac{2 x}{3} - \frac{3 x}{8} = \frac{7}{12} (i i i) (x + 2) (x + 3) + (x - 3) (x - 2) - 2 x (x + 1) = 0 (i v) \frac{1}{10} - \frac{7}{x} = 35 (v) 13 (x - 4) - 3 (x - 9) - 4 (x + 4) = 0 (v i) x + 7 - \frac{8 x}{3} = \frac{17 x}{6} - \frac{5 x}{8} (v i i) \frac{3 x - 2}{4} - \frac{2 x + 3}{3} = \frac{2}{3} - x (v i i i) \frac{x + 2}{6} - (\frac{11 - x}{3} - \frac{1}{4}) = \frac{3 x - 4}{12} (i x) \frac{2}{5 x} - \frac{5}{3 x} = \frac{1}{15} (x) \frac{x + 2}{3} - \frac{x + 1}{5} = \frac{x - 3}{4} - 1 (x i) \frac{3 x - 2}{3} + \frac{2 x + 3}{2} = x + \frac{7}{6} (x i i) x - \frac{x - 1}{2} = 1 - \frac{x - 2}{3} (x i i i) \frac{9 x + 7}{2} - (x - \frac{x - 2}{7}) = 36 (x i v) \frac{6 x + 1}{2} + 1 = \frac{7 x - 3}{3}$

Solve : (i) 13x−6=52(ii) 2x3−3x8=712(iii) (x+2)(x+3)+(x−3)(x−2)−2x(x+1)=0(iv) 110−7x=35(v) 13(x−4)−3(x−9)−4(x+4)=0(vi) x+7−8x3=17x6−5x8(vii) 3x−24−2x+33=23−x(viii) x+26−(11−x3−14)=3x−412(ix) 25x−53x=115(x) x+23−x+15=x−34−1(xi) 3x−23+2x+32=x+76(xii) x−x−12=1−x−23(xiii) 9x+72−(x−x−27)=36(xiv) 6x+12+1=7x−33

Answer»

Solve :

$(i) \frac{1}{3} x - 6 = \frac{5}{2} (i i) \frac{2 x}{3} - \frac{3 x}{8} = \frac{7}{12} (i i i) (x + 2) (x + 3) + (x - 3) (x - 2) - 2 x (x + 1) = 0 (i v) \frac{1}{10} - \frac{7}{x} = 35 (v) 13 (x - 4) - 3 (x - 9) - 4 (x + 4) = 0 (v i) x + 7 - \frac{8 x}{3} = \frac{17 x}{6} - \frac{5 x}{8} (v i i) \frac{3 x - 2}{4} - \frac{2 x + 3}{3} = \frac{2}{3} - x (v i i i) \frac{x + 2}{6} - (\frac{11 - x}{3} - \frac{1}{4}) = \frac{3 x - 4}{12} (i x) \frac{2}{5 x} - \frac{5}{3 x} = \frac{1}{15} (x) \frac{x + 2}{3} - \frac{x + 1}{5} = \frac{x - 3}{4} - 1 (x i) \frac{3 x - 2}{3} + \frac{2 x + 3}{2} = x + \frac{7}{6} (x i i) x - \frac{x - 1}{2} = 1 - \frac{x - 2}{3} (x i i i) \frac{9 x + 7}{2} - (x - \frac{x - 2}{7}) = 36 (x i v) \frac{6 x + 1}{2} + 1 = \frac{7 x - 3}{3}$

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