[size=14]I need a batch
to detect if a cd is inserted in a CD-ROM drive, if it is not I
have to look in the other CD-ROM

please help[/size]Try this code:

--------------cdready.bat--------------
@echo off

dir S:\ > NUL 2> NUL
if errorlevel 1 goto TRY_T
SET unit=S:
goto RUN

:TRY_T
dir T:\ > NUL 2> NUL
if errorlevel 1 goto NO-CD
SET unit=T:

:RUN
call %unit%\Prog\x.exe
goto END

:NO-CD
echo Sorry, I can't fint the program X.exe

:END
--------------------------------[size=16]
It dos't work [/size]You haven't been very forthcoming with your OS. It might have also been helpful had you MENTIONED why the PREVIOUS solution did not work (incorrect results? syntax error? etc)

This code snippet will run in Windows. It's based on your original post.

Code: [Select]Set fso = CreateObject("Scripting.FileSystemObject")
Set objShell = CreateObject("WScript.Shell")
For Each d In fso.Drives
If d.DriveType = 4 Then
If d.IsReady Then
If fso.FileExists(d.driveletter & ":\prog\x.exe") Then
objShell.CurrentDirectory = "a:\"
objShell.Run "main.bat",,True
WScript.Quit
End If
End If
End If
Next
WScript.Echo "X.exe Not Found on Any CD"

Save the script with a VBS extension and run from the command line as cscript scriptname.vbs

Good luck. 8-)[size=14]Sorry if I was not clear enough

The error message is :

TOO MANY PARAMETERS – 2

I'm using windows xp and as you know if I boot the machine it means DOS.

I want to boot my pc with a bootable cd and run a batch to check where is the folder of my programs is it in the cd in cd rom #1 or #2 other wise it will give an error message


Thanks to both of you[/size] Quote

I'm using windows xp and as you know if I boot the machine it means DOS