I would like to know how to display a number in reverse using BATCH file programming eg. 20060211 to be displayed as 11206002

My os is winxp pro

THANKS@echo off
set number=20060211
set aux=%number%

set REV=

:LOOP
if "%aux%"=="0" goto END
set last_digit=%aux:~-1%
set REV=%REV%%last_digit%
set /A aux=%aux%/10
goto LOOP

:END
echo The reverse of %number% is %REV%Carlos, thanks for your quick response, but I should have been more specific. The number(date) is generated by the program listed below and would of course change every day

set sDate=%DATE:~10,4%%DATE:~4,2%%DATE:~7,2%

but I need the date generated to be in reverse, eg. instaed of 20060212 I would like it displayed as 21206002

ThanksIt's an EASY exercise to replace the line:
set number=20060211
for:
set sDate=%DATE:~10,4%%DATE:~4,2%%DATE:~7,2%

Here is a possible solution:


@echo off
set sDate=%DATE:~10,4%%DATE:~4,2%%DATE:~7,2%
echo Date: %sDate%
set aux=%sDate%

set sDate=

:LOOP
if "%aux%"=="0" goto END
set last_digit=%aux:~-1%
set sDate=%sDate%%last_digit%
set /A aux=%aux%/10
goto LOOP

:END
echo Reverse Date: %sDate%

P.S. If you copy and paste this code, be carefull with the white spaces at the end of the lines. you must suppress them.Carlos, that worked perfectly

one last question, how would I TAKE this reversed result and divide it by the number 4421 then display the result so that the first 4 digits after the decimal point is displayed.

ps what would you suggest as a good tutorial for laerning this type of programming

thanks again for all your helpMS-DOS haven't decimal numbers, you can do the next:

@echo off
set sDate=31216002 <-- replace this line ...

set /A integer=%sDate%/4421
set /A remainder=(%sDate% - 4421*integer)%4421
set /A fracc=10000*remainder/4421

set sol=%integer%.%fracc%

echo Division with four decimasl: %sol%


Sorry, I'm from Spain and here I don't know GOODS books of MS-DOS (I don't know if in your country ...) Perhaps the best book is the documentation:

SET /?

and to know a bit of mathematics

The used formula in the quotient:

D | d
r c

is:

D=d*c + rCarlos,thanks again for your great help , this is what i have so far

@echo off
set sDate=%DATE:~10,4%%DATE:~4,2%%DATE:~7,2%
set aux=%sDate%

set sDate=

:LOOP
if "%aux%"=="0" goto END
set last_digit=%aux:~-1%
set sDate=%sDate%%last_digit%
set /A aux=%aux%/10
goto LOOP

:END
echo %sDate%

set /A integer=%sDate%/4421
set /A remainder=(%sDate% - 4421*integer)%4421
set /A fracc=10000*remainder/4421

set sol=%integer%.%fracc%

echo Division with four decimasl: %sol%


** when I run this I get the answer 7058.5044 which is correct but all I need is the first 4 digits after the decimal point (5044) to be displayed. I also get a missing operator message when the above is run