Solve : IF statement with variable?

1.	Solve : IF statement with variable?
Answer» Hello, I am TRYING to create a bat file that will do something based on the last octet of the ip of the MACHINE. I have already MADE something that gets the ip (from the registry) takes the last three digits and stores it as a variable (ip). Now I am having trouble with the IF statements. To make it easier I just STARTED at the highest group of ips, used greater than (GTR) and worked my way down. In the labels I exit the script after it does what I need so it is only possible to enter one IF statement. Each if statement sends it to the appropriate label to do what I need that computer to do. IF %ip% GTR 200 GOTO group1 END IF %ip% GTR 190 GOTO group2 END ......and so on...... group1: ......do stuff....... EXIT group2: .....do stuff........ EXIT I am PRETTY sure that my problem is with the IF statements, but I am not sure what I am doing wrong. Thank you in advance for reading through this and I look forward to any guidance anyone can offer.Quote from: fjwolz19 on May 29, 2007, 06:38:56 AM I am pretty sure that my problem is with the IF statements, but I am not sure what I am doing wrong. Thank you in advance for reading through this and I look forward to any guidance anyone can offer. Your problem is, that code is not batch language. It is some other language maybe not yet invented. There are 2 problems. The IFs and the labels. (1) IF statements in batch are usually like this on one line. You don't have "END". IF %ip% GTR 200 goto group1 IF %ip% GTR 190 goto group2 (2) You got the labels back-to-front. The colon goes BEFORE the label name :group1 .....do stuff.... EXIT :group2 .....do stuff.... EXIT It is not compulsory to put anything in a batch file in capital letters. If you want a multiline if, use braces (parentheses) like this if %ip% gtr 200 ( echo it was more than 200 echo another line goto group1 ) :group1 Or use & like this if %ip% gtr 200 echo more than 200 & echo some more text & goto group1

Answer»

Hello,
I am TRYING to create a bat file that will do something based on the last octet of the ip of the MACHINE. I have already MADE something that gets the ip (from the registry) takes the last three digits and stores it as a variable (ip). Now I am having trouble with the IF statements. To make it easier I just STARTED at the highest group of ips, used greater than (GTR) and worked my way down. In the labels I exit the script after it does what I need so it is only possible to enter one IF statement. Each if statement sends it to the appropriate label to do what I need that computer to do.

IF %ip% GTR 200
GOTO group1
END

IF %ip% GTR 190
GOTO group2
END

......and so on......

group1:
......do stuff.......
EXIT

group2:
.....do stuff........
EXIT

I am PRETTY sure that my problem is with the IF statements, but I am not sure what I am doing wrong. Thank you in advance for reading through this and I look forward to any guidance anyone can offer.Quote from: fjwolz19 on May 29, 2007, 06:38:56 AM

I am pretty sure that my problem is with the IF statements, but I am not sure what I am doing wrong. Thank you in advance for reading through this and I look forward to any guidance anyone can offer.

Your problem is, that code is not batch language. It is some other language maybe not yet invented.

There are 2 problems. The IFs and the labels.

(1) IF statements in batch are usually like this on one line. You don't have "END".

IF %ip% GTR 200 goto group1
IF %ip% GTR 190 goto group2

(2) You got the labels back-to-front. The colon goes BEFORE the label name

:group1
.....do stuff....
EXIT

:group2
.....do stuff....
EXIT

It is not compulsory to put *anything* in a batch file in capital letters.

If you want a multiline if, use braces (parentheses) like this

if %ip% gtr 200 (
echo it was more than 200
echo another line
goto group1
)

:group1

Or use & like this

if %ip% gtr 200 echo more than 200 & echo some more text & goto group1

Solve : IF statement with variable?

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