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Solve it. Challenge |
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Answer» -step explanation:we know one theorem that if you draw a line perpendicularly from the centre to a chord then that line divides that chord into two equal parts so in the the POINT of intersection of PQ and AB take it as X so according to the above theoremXC= XD( for SMALLER circle) XA= XB( for bigger circle) so the value of ACDB= 2√15so AX = 2√15/2= √15now O'A =4 (radius of bigger circle) so by Pythagoras theorem for the right triangle O'XA O'A^2= O'X^2+XA^216= O'X^2+15O'X^2=16-15=1O'X= 1AND the DISTANCE between XO = 1+(4-3)=1+1=2OA^2= OX^2+XA^2= 4+15OA = √19we need to find the value of XC in order to find the value of ACso in the triangle XOCOC=3(radius )XO=2so XC^2= 3^2-2^2= 9-4=5XC= √5so now AC= AX-XC =√15-√5= √5(√3-1) |
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