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Answer» Ranjan and Rohit had coins in the ratio 11:7 Let, the common multiple be x Then, Ranjan had 11X coins and Rohit had 7x coins By the given condition, 11x + 7x = 468 or, 18x = 468 or, x = 468/18 or, x = 26 So, Ranjan had (11 × 26) = 286 coins and Rohit had (7 × 26) = 182 coins Ranjan's MOTHER gave him 14 more coins; so he has (286 + 14) = 300 coins now Let us take Rohit's mother TOOK y number of coins from him; so he has (182 - y) coins now By the given condition, 300 : (182 - y) = 15 : 8 or, 300/(182 - y) = 15/8 or, 15 (182 - y) = 300 × 8 or, 182 - y = (300/15) × 8 or, 182 - y = 20 × 8 = 160 Therefore, Rohit has 160 coins now. # |
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