Solve: \(\lim\limits_{x \to 0}\Big(\frac{2^x - 1}{3x}\Big)\)

1.	Solve: \(\lim\limits_{x \to 0}\Big(\frac{2^x - 1}{3x}\Big)\)
Answer» = \(\lim\limits_{x \to 0}\frac{2^x - 1}{x} \times \frac{1}{3}\) = log_e2 x \(\frac{1}{3}\) = \(\frac{log_e2}{3}\)

Answer»

= \(\lim\limits_{x \to 0}\frac{2^x - 1}{x} \times \frac{1}{3}\)

= log_e2 x \(\frac{1}{3}\) = \(\frac{log_e2}{3}\)

Discussion

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