1.

Solve: \(\lim\limits_{x \to0}\frac{sin4x}{sin2x}\)

Answer»

\(\frac{\lim\limits_{x \to 0}\frac{sin4x}{4x} . 4x}{\lim\limits_{x\to0}\frac{sin2x}{2x}.2x}\)

\(\frac{1\times 4}{1 \times2} = 2\)



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