how do i make a batch file wait for 5SEC befor it exitsIts very complicated
you have to create a batch named wait.bat in the windows folder,in that batch type :
@CHOICE /T:N,%1% > NUL
than when you want to wait you just type :
wait and the number of seconds you want to wait

Hope it helps

Almni have a bat file that dose its thing and says DONE!!!! when it is done
but i want done to display for 5sec and the the program would end than put it after "echo done"

Almndoes not work
There is a workaround with the ping command. It was posted a few month before.

Otherwise use the SLEEP command from the ressource kit.

sleep 5

hope this helps
ulihere is somthing i made
Code: [Select]@echo off
set count1=0

:loop
@cls
echo Working.
echo %count1%
set/a count1=count1+1
IF "%count1%" EQU "500" (
goto :dot
) ELSE (
goto :loop
)
:dot
@cls
echo Working..
echo %count1%
set/a count1=count1+1
IF "%count1%" EQU "1000" (
goto :dot2
) ELSE (
goto :dot
)
:dot2
@cls
echo Working...
echo %count1%
set/a count1=count1+1
IF "%count1%" EQU "1500" (
goto :part2
) ELSE (
goto :dot2
)
:part2
:loop2
@cls
echo Done!!!
echo %count1%
set/a count1=count1+1
IF "%count1%" EQU "3000" (
goto :end
) ELSE (
goto :loop2
)
:end

this is not a batch solution..
just that sometimes, its much easier to program with a better scripting language than batch.

#python example
import time
do_something()
time.sleep(5) #sleep 5 secs
do_anotherthing()

Code: [Select]@echo off
set count1=0
echo Done!!!
:loop
set/a count1=count1+1
IF "%count1%" EQU "1000" (
goto :end
) ELSE (
goto :loop
)
:end
this does the trick