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Solve : Only typing certain parts of a text file? |
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Answer» HI all! I was wondering if it's possible - and if so, how? - to print only a certain part of a text file with the type COMMAND. e.g: Text file: Quote
How would i go about printing only say, the bit Quote chocolate? Thanks in advance, Kamak i also would like to know this. sorry I'm of no help.u cant us the type command alone to generate such an output put u can type out som lines of the file @echo off setlocal ENABLEDELAYEDEXPANSION set /a cont=1 for /f "delims=" %%i in (file.txt) do ( if "!count!" EQU "3" echo %%i set /a count=!count!+1 ) endlocal this code will print the 3rd line if u want it to print from the 3 to 5 row u have to do this @echo off setlocal ENABLEDELAYEDEXPANSION set /a count=1 set /a count2=3 for /f "delims=" %%i in (New.txt) do ( if "!count2!" GTR "5" set /a count2=0 if "!count!" EQU "!count2!" ( echo %%i set /a count2=!count2!+1 ) set /a count=!count!+1 ) endlocal pauseQuote from: .bat_man on June 12, 2008, 10:50:53 AM u cant us the type command alone to generate such an outputThank You welcom welcomWhat if you wanted only certain lines. Say lines 3, 5, 8, etc.?Think I got it. At least it is doing what I want. Anyone have a cleaner way to do this, post for all to enjoy. if EXIST File2 del file2 setlocal ENABLEDELAYEDEXPANSION set count=0 for /f %%v in (File1) do ( set /a count=!count!+1 echo !count! if !count!==3 echo %%v > File2 if !count!==5 echo %%v >> File2 if !count!==10 echo %%v >> File2 if !count!==70 echo %%v >> File2 if !count!==71 echo %%v >> File2 if !count!==72 echo %%v >> File2 ) |
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