1.

Solve : PHP _GET function won't work on "if" statements?

Answer»

if ($link = _GET['none']) { alert('None is in your WINDOWS location!') }You're GETTING mixed up with JavaScript and PHP. PHP cannot display alerts, it can only echo the JS code to display it.

Quote from: Bannana97 on April 04, 2009, 06:23:58 PM

if ($link = _GET['none']) { alert('None is in your windows location!') }

Try:

Code: [Select]if ($link = $_GET['none'])
{
  echo "<script type='text/javascript'>alert('None is in your windows location!') </script>";
}
Nope. Heres the entire code:




function doAction() {
var searchFOR = document.getElementById('inta')

if (searchFOR.value == 'HerbertsWorld') {
window.location = "http://www.herbertsworld.com/members.php?membersID=all&category=rate&input=found&search=" + searchFOR.value
document.getElementById('NotFound').style.display = 'none';
 }
else if (searchFOR.value == 'herbertsworld') { 
window.location = "http://www.herbertsworld.com/members.php?membersID=all&category=rate&input=found&search=" + searchFOR.value
document.getElementById('NotFound').style.display = 'none';
 }
else {
document.getElementById('NotFound').style.display = 'block';

window.location = "http://www.herbertsworld.com/members.php?membersID=all&category=rate&input=none&search=" + searchFOR.value
 }

}

function hideResult() {
if ($link = $_GET['none']) {
document.getElementById('NotFound').style.display = 'block'; }
else {
document.getElementById('NotFound').style.display = 'none' }
}
that's the opposite- your trying to put PHP code in a javascript FILE.How would I do it though?Wait its not a js file. Its a .php file.The only php code is the get.

yes but I named the file members.php

It worked before. Then it broke. Quote from: Bannana97 on April 05, 2009, 12:37:07 PM
yes but I named the file members.php

That won't do anything.



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