I have a DIRECTORY with filenames that have a % (percent sign) in the name. I need to rename all files with "%" sign to an "_" underscore. Any ideas how I can create a loop to do this in DOS batch [not VB]?

The code below will convert spaces to underscores, not sure how to handle percent signs.

@echo off & setlocal enableextensions
pushd "%ENCRYPTED_PATH%"
for /f "tokens=*" %%f in ('
dir /b /a-d-s "%ENCRYPTED_PATH%\* *.*"') do (
set "_=%%~nxf"
call ren "%%~ff" "%%_: =_%%"
)
popd
endlocalI thought percent signs are illegal in Windows filenames, just how did these files get on your system?
The following should replace a percent sign with a # in each filename encountered. Remove echo when happy. I have not got any files with % in the name so I created a DUMMY set in a text file but this should work...

Code: [Select]@echo off
setlocal enabledelayedexpansion
dir /b /a-d-s "%ENCRYPTED_PATH%\* *.*" > test.txt
for /f "delims=" %%A in (test.txt) do (
set string1=%%A
set string2=!string1:%%=#!
echo ren "!string1!" "!string2!"
)

In cmd scripts ("batch files") you need to escape certain special characters. For many symbols the escape char is a CARET (^) but for a percent sign the escape character is... a percent sign. So double them up.

Quote from: Salmon Trout on October 27, 2009, 01:40:56 PM

I thought percent signs are illegal in Windows filenames, just how did these files get on your system?