Hallo to everybody. I'm an italian user, so please forgive my poor english. I follow you from a lot of time but now I need your help so I've REGISTERED myself.

Now I explain my problem. I have to loop recursively a folder in order to find all the files that starts with 6 digits followed by some text, let's say A.csv.

I wrote this

dir /b /s | findstr /i ^[0-9][0-9][0-9][0-9][0-9][0-9]A.csv$

and it works but this command returns me the full paths. I'd like to have only filename. I know about the for command and ~n but I don't know if I can use it with findstr. Thanks in advance. for /f can parse the output of a command line. Use single quotes.

CODE: [Select]for /f "delims==" %%F in ('dir /b /s ^| findstr /i ^[0-9][0-9][0-9][0-9][0-9][0-9]A.csv$') do (
echo %%F
)

Code: [Select]S:\Test\Batch\After 07-09-09\forfind\123452A.csv
S:\Test\Batch\After 07-09-09\forfind\123453A.csv
S:\Test\Batch\After 07-09-09\forfind\123454A.csv
S:\Test\Batch\After 07-09-09\forfind\123455A.csv
S:\Test\Batch\After 07-09-09\forfind\123456A.csv
S:\Test\Batch\After 07-09-09\forfind\123451A.csv

~nxVariable is name + extension. See for /? for full list of variable modifiers.

remember to ESCAPE the pipe symbol | like this ^| or you will get an error

Code: [Select]for /f "delims==" %%F in ('dir /b /s ^| findstr /i ^[0-9][0-9][0-9][0-9][0-9][0-9]A.csv$') do (
echo %%~nxF
)

Code: [Select]123452A.csv
123453A.csv
123454A.csv
123455A.csv
123456A.csv
123451A.csv
Thank you very much Salmon. I didn't know about the escape char, indeed without it I received an error and this was the reason why I thought I couldn't use findstr within for. I've learned a NEW thing.
Thanks again for your kindness and for the speed of your reply. Have a nice day. va bene