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Solve sec `4 theta- sec 2 theta=2`. |
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Answer» `1/(cos 4 theta)-1/(cos 2 theta)=2` or `cos 2 theta-cos 4 theta =2 cos 2 theta cos 4 theta = cos 2 theta + cos 6 theta` or `cos 6 theta + cos 4 theta=0` or `2 cos 5 theta cos theta =0` `rArr cos 5 theta=0" "or cos theta =0` `rArr 5 theta=(2n+1) pi/2 or theta=(2n+1) pi/2, n in Z` `rArr theta=(n+1/2) pi/5 or theta=(n+1/2) pi, n in Z` |
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