InterviewSolution
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InterviewSolution
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Solve `sec theta-1=(sqrt(2)-1) tan theta`. |
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Answer» Correct Answer - `theta=2npi or theta=2n pi +pi/4, n in Z` `sec theta-1=(sqrt(2)-1) tan theta` `rArr ((1-cos theta)/(cos theta))=((sqrt(2)-1) sin theta)/(cos theta)` or `2 sin^(2) (theta//2)=(sqrt(2)-1)2 sin (theta//2) cos (theta//2)` or `sin (theta//2)=0, tan (theta//2)=(sqrt(2)-1)=tan (pi//8)` `rArr theta//2=n pi or theta/2=npi +pi/8, n in Z` `rArr theta=2n pi or theta=2 n pi +pi/4` |
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