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Solve `sin 2 theta+cos theta=0`. |
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Answer» We have `sin 2 theta+cos theta=0` or `cos theta=- sin 2 theta = cos (pi/2+2 theta)` `rArr theta=2 n pi pm (pi/2+2 theta) n in Z` Taking positive sign, we have `theta=2 npi + pi/2 +2 theta` `theta=2 n pi - pi/2, n in Z` Taking negative sign, we have `theta=2 n pi -(pi/2+2 theta)` `rArr theta=(2 n pi)/3-pi/6, n in Z` |
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