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Solve `sin 2x+cos 4x=2`. |
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Answer» Correct Answer - No solution `sin 2x+cos 4x=2` It is possible only when `sin 2x=1` and `cos 4x=1` `2x=2npi+pi/2 and 4x=2mpi` `:. X= npi +pi/4 and x= (mpi)/2`, where `m, n in Z` Then, solution is given by `(n pi +pi/4, n in I) nn ((mpi)/2, m in Z)= phi` |
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