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Solve `sin 3 theta-sin theta=4 cos^(2) theta-2`. |
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Answer» Correct Answer - `theta=(2n+1) pi/4, n in Z or theta =(4n+1) pi/2, n in Z` `sin 3 theta- sin theta=4 cos^(2) theta-2` `rArr 2 sin theta cos 2 theta=2 cos 2 theta` `rArr cos 2 theta=0` or ` sin theta=1` `rArr 2 theta=(2n+1) pi/2, n in Z` or `theta=(4n+1) pi/2, n in Z` or `theta=(2n+1) pi/4, n in Z`, or `theta=(4n+1) pi/2, n in Z` |
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