1.

Solve `sin 3 theta-sin theta=4 cos^(2) theta-2`.

Answer» Correct Answer - `theta=(2n+1) pi/4, n in Z or theta =(4n+1) pi/2, n in Z`
`sin 3 theta- sin theta=4 cos^(2) theta-2`
`rArr 2 sin theta cos 2 theta=2 cos 2 theta`
`rArr cos 2 theta=0` or ` sin theta=1`
`rArr 2 theta=(2n+1) pi/2, n in Z` or `theta=(4n+1) pi/2, n in Z`
or `theta=(2n+1) pi/4, n in Z`, or `theta=(4n+1) pi/2, n in Z`


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