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Solve `sin^3thetacostheta-cos^3thetasintheta=1/4dot` |
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Answer» `sin^(3) theta cos theta-cos^(3) theta sin theta =1/4` or `4 sin theta cos theta(sin^(2) theta - cos^(2) theta)=1` or `2 sin 2 theta (-cos 2 theta)=1` or `- sin 4 theta=1` or `sin 4 theta=-1` `rArr 4 theta=2 n pi - pi/2` `rArr theta= (n pi)/2-pi/8, n in Z` |
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