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Solve `sin theta+cos theta=sqrt(2) cos A`. |
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Answer» Correct Answer - `theta=2n pi +pi/4 pm A, n in Z` `sin theta + cos theta=sqrt(2) cos A` `rArr (1//sqrt(2)) sin theta +(1//sqrt(2)) cos theta=cos A` or `cos (theta-pi//4)=cos A` `rArr theta-pi//4=2npi pm A` or `theta=2npi+pi//4 pm A, AA n in Z` |
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