Solve `sin x tan x -sin x+ tan x-1=0` for `x in [0, 2pi]`. – InterviewSolution

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1.	Solve `sin x tan x -sin x+ tan x-1=0` for `x in [0, 2pi]`.
Answer» Correct Answer - `x= pi/4, (5 pi)/4` `sin x tan x-sin x+tan x-1=0` `rArr tan x(sin x+1)-(sin x +1)=0` `rArr (sin x+1) (tan x-1) =0` `rArr sin x=-1` or `tan x=1` For `sin x=-1, tan x` is not defined (as cos x=0). `:. tan x=1` `:. x=pi/4, (5pi)/4`

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