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| 1. |
Solve `sqrt(3)` sec `2 theta=2`. |
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Answer» We have `sqrt(3) sec 2 theta=2` or `cos 2 theta=sqrt(3)/2=cos pi/6` `rArr 2theta=2npi pm pi/6, n in Z` or `theta=npi pm pi/12, n in Z` |
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