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Solve that following equations :`sec x cos 5x+1=0,` `0 lt x le pi/2` find the value of x

Answer» `secx*cos5x+1=0`
`(cos5x)/cosx=-1`
`cos5x=-cosx`
`cos5x+cosx=0`
`2cos((5x+x)/2)*cos((5x-x)/2)=0`
`2ocs3x*cos2x=0`
`cos3x=0`
`3x=pi/2,3/2pi`
`x=pi/6,pi/2`
`cos2x=0`
`2x=pi/2`
`x=pi/4`.


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