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Solve that following equations :`"tantheta"+"tan"2"theta"+sqrt(3)"tanthetatan"2"theta"=""sqrt(3)` |
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Answer» `sintheta/costheta+(cos2theta)/cos2theta+sqrt3sintheta/costheta*(sin2theta)/cos2theta=sqrt3` `(sinthetacos2theta+sin2thetacostheta+sqrt3sinthetasin2theta)/(costhetacos2theta)=sqrt3` `sin(theta+2theta)+sqrt3(sinthetasin2theta-costhetacos2theta)=0` `sin3theta-sqrt3(costhetacostheta-sinthetasin2theta)=0` `sin3theta-sqrt3cos3theta=0` `tan3theta=sqrt3` `theta=pi/9` General solution `theta=pi/9pmnpi`. |
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