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Solve the differential equation `(dy)/(dx)=sin^(4)x*cosx`. |
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Answer» `(dy)/(dx)=sin^(4)x*cosx` Integrate both sides with respect to `x` `int(dy)/(dx)*-dx=intsin^(4)x cosx dx+c` Let `sinx=t` `implies intdy=intt^(4)*-dt+-cimpliescosx=-(dt)/(dx)` `cosxdx=dt` `implies y=(1)/(5)t^(5)+c` `implies y=(1)/(5)sin^(5)x+c`. |
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