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Solve the equation `sqrt((6-x))(3^(x^(2)-7.2x+3.9)-9sqrt(3))=0` |
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Answer» We have `sqrt((6-x))(3^(x^(2)-7.2x+3.9)-9sqrt(3))=0` This equation is defined for `6-xge0`. i.e. `xle6` …….i This equation is equivalent to the collection of equations `sqrt(6-x)=0` and `3^(x^(2)-7.2x+3.9)-9sqrt(3)=0` `:.x_(1)=6` and `3^(x^(2)-7.2x+3.9)=3^(2.5)` Then `x^(2)-7.2x+3.9=2.5` `x^(2)-7.2x+1.4=0` We find that `x_(2)=1/5` and `x_(3)=7` Hence solution of the original equation are [which satisfies Eq.(i) ] `x_(1)=6,x_(2)=1/5` |
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