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Solve the following : (a) `1 le |x-2| le 3 " (b) "0 lt |x-3|le 5` (c ) `|x-2|+|2x-3|=|x-1| " (d) " |(x-3)/(x+1)| le1` |
Answer» Correct Answer - (a) `[-1,1]cup [3,5] " (b) " [-2,8]-{3} " (c ) " [3//2,2] " (d) "[1,oo)` (a) ` 1 le |x-2| le 3` `implies-3 le x-2 le -1 " or " 1 le x-2 le 3` `implies -1 le x le 1 " or "3 le x le 5` (b) ` 0 lt |x-3| le 5` `implies -5 le x-3 le 5, x-3 ne 0` `implies -2 le x le 8, x ne 3` (c ) `|x-2| +|2x-3|=|x-1|` `implies |x-2|+|2x-3|=|(2x-3)-(x-2)|` `implies (x-2) (2x-3) le 0` `implies 3//2 le x le 2` (d) `|(x-3)/(x+1)| le 1` `implies -1 le (x-3)/(x+1) le 1` `implies 0 le (x-3)/(x+1)+1 " and " (x-3)/(x+1)-1 le 0` `implies0 le (2x-2)/(x+1) " and " (-4)/(x+1) le 0` `implies x le -1 " or " x ge 1 " and " x gt -1` `implies x ge 1` |
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