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Solve the following differential equations:`(dy)/(dx)=1+x+y+x y`(ii)`y-x(dy)/(dx)=a(y^2+(dy)/(dx))` |
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Answer» Correct Answer - `y/(1-ay)=c(a+y)` `y-x(dy)/(dx)=a(y^(2)+(dy)/(dx))` or `int(dx)/(a+x)=int(dy)/(y-ay^(2))=int(1/y+a/(1-ay))dy` [By partial fractions] Integrating we get `log(a+x)+logc=logy-log(1-ay)` Which is arbitary positive constant. Thus, the solution can be written as `y/(1-ay)=c(a+x)` |
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