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Solve the following equation by trial and error method : (i) 3 X + 5 = 14 (ii) 2p – 7 = 5 |
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Answer» have 3x + 5 = 14 Putting x=1 in LHS , we get 3 (1) + 5 = 3 + 5 = 8 ≠ RHS Putting x = 2 in LHS , we get 3(2)+ 5 =6+5=11≠RHSPutting x=3 in LHS , we get 3(3)+5 = 9+5=14 = RHSHere ,x=3 is the solution of the equation 3x + 5 = 142).We have 2p-7 = 5Putting P=1 in LHS ,we get 2(1)-7 = 2-7 = -5Putting p = 2 in LHS ,we get 2(2)-7=4-7 = -3Putting p=3 in LHS ,we get 2(3)-7 = 6 – 7 = -1Putting p = 4 in LHS , we get 2(4) – 7 = 8 – 7 = 1Putting p= 5 in LHS , we get 2(5) – 7 = 10-7 = 3Putting p= 6 in LHS ,we get2(6) – 7 = 12 – 7 = 5Here , p=6 is the solution of the equation 2p-7=5 |
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