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Solve the following equationsgraphically and find the least valueof y.26a [2x^2 - 3x+ 1 = 0] note x is a letter |
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Answer» GIVEN 2x +3x+1=0 On comparing this equation with ax 2 +bx+c=0, where a=2,b=3,c=1 ∴ b 2 −4ac=(5) 2 −4×2×1 =9−8 =1 x= 2a −b± b 2 −4ac
= 2×2 −3± 1
x= 4 −3+1
or x= 4 −3−1
x= 4 −2
or x= 4 −4
x= 2 −1
or x=−1 if it helps then mark me as braineliest!!!! |
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