1.

Solve the following equationsgraphically and find the least valueof y.26a [2x^2 - 3x+ 1 = 0] note x is a letter​

Answer»

ANSWER:

GIVEN 2x

2

+3x+1=0

On comparing this equation with ax

2

+bx+c=0, where a=2,b=3,c=1

∴ b

2

−4ac=(5)

2

−4×2×1

=9−8

=1

x=

2a

−b±

b

2

−4ac

=

2×2

−3±

1

x=

4

−3+1

or x=

4

−3−1

x=

4

−2

or x=

4

−4

x=

2

−1

or x=−1

if it helps then mark me as braineliest!!!!



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