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Solve the following for x, where |x| is modulus function, [x] is the greatest integer function, {x} is a fractional part function.|x2 – x – 6| = x + 2 |
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Answer» |x2 – x – 6| = x + 2 …..(i) R.H.S. must be non-negative ∴ x ≥ -2 …..(ii) |(x – 3) (x + 2)| = x + 2 ∴ (x + 2) |x – 3| = x + 2 as x + 2 ≥ 0 ∴ |x – 3| = 1 if x ≠ -2 ∴ x – 3 = ±1 ∴ x = 4 or 2 ∴ x = -2 also satisfies the equation ∴ Solution set = {-2, 2, 4} |
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