1.

solve the following pair of linear equation by the method of cross multiplication (a+b) x+(a-b) y=a² + 2ab-b²;a=0​

Answer»

(a−b)X+(a+b)y=a 2 −2ab−b 2 ----- (i)(a+b)(x+y)=a 2 +b 2 -------- (ii)SUBTRACTING eq (i) by eq (ii), we get.⇒(a−b)x−(a+b)x=a 2 −2ab−b 2 −a 2 −b 2 ⇒−2bx=−2bx(a+b)⇒x=(a+b)∴(a+b)(a+b+y)=a 2 +b 2 ⇒(a+b) 2 +(a+b)y=a 2 +b 2 ⇒y= a+b−2ab ANS.



Discussion

No Comment Found